for (int x = 0; x < 60; x++)//x是压测多少秒

{

for (int j = 0; j < 100; j++)//j是并发数

{

Task.Run(async () =>

{

//for (int i = 0; ; i++)

for (int i = 0; i < 100; i++)//i是每个并发下执行多少次如果压测行为是起task的每秒钟的并发就是i*j

{

{

DateTime tt1 = DateTime.Now;

Task.Run(() =>

{

//压测行为

});

double time = (DateTime.Now - tt1).TotalMilliseconds;

if (time < 1000)

{

await Task.Delay((int)(1000 - time));

}

}

}

});

}

System.Threading.Thread.Sleep(1000);

break;

}